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General Chemistry for Tristan #73073
How many moles of PCl5 can be produced from 60.0 g of Cl2 (and excess P4)?
Express your answer to three significant figures and include the appropriate units.
2P + 5Cl2 => 2PCl5
m(Cl2 )= 60.0 g
m(PCl5) – ?
n(Cl2) = m(Cl2)/ M(Cl2) = 60.0 g / 71 g/mol = 0.845 mol
2n(PCl5) = 5n(Cl2 )
n(PCl5) = 2n(Cl2 )/ 5 = 2*0.845 mol/ 5 = 0.338 mol
m (PCl5) = n(PCl5) *M(PCl5) = 0.338 mol*208 g/mol = 70.304 g
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Answer to Question #73073 in General Chemistry for Tristan
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Frequently Asked Questions About how many moles of pcl5 can be produced from 60.0 g of cl2 (and excess p4)?
If you have questions that need to be answered about the topic how many moles of pcl5 can be produced from 60.0 g of cl2 (and excess p4)?, then this section may help you solve it.
From 59.0 g of Cl2 and extra P4, how many moles of PCl5 can be created?
From 54.0 g of Cl2 and extra P4, how many moles of PCl5 can be created?
As a result, extra phosphorus will result in the formation of 0.310 moles of PCl5 (assuming the reaction is successful).
From 21.0 g of P4 and extra Cl2, how many moles of PCl5 can be created?
Answered by an Expert: “1776 moles” In the reaction, 4 moles of PCl5 are created for each mole of P4 that reacts.
From 60 g of Cl2, how many moles of PCl5 can be produced?
Express your response to three significant figures and use the appropriate units for General Chemistry I. 0.339 moles of PCl? will form at the conclusion of the reaction because of the following equation: 0.8463 mole of Cl? (g)? 0.8463 mol? 0.4 mol = 0.33852 mole? 0.339 mole.
How do you figure out how many moles of product a reaction produces?
Step 1: Balance the chemical reaction. Step 2: Determine the ratio of the stoichiometric coefficients of the reactant and the product. Step 3: Multiply the ratio from Step 2 by the specified number of moles of the reactant.
55 g of Cl2 can be converted into how many moles of PCl5?
In light of this, 0.310 moles of PCl5 P C l 5 can be created from 55.0 grams of Cl2 C l 2.
From 28.0 g of p4, how many moles of PCl5 can be produced?
The amount of PCl5 produced, in moles, is 0.9041 moles.
When 8 mol of P and 5 mol of Q are allowed to react in accordance with the equation, how many moles of are will be produced?
So, 4 is the right response.
When 8 mol of P and 5 mol of Q are allowed to react in accordance with the equation 2p q r, how many moles of are they going to produce?
4 mol of R will be created from 8 mol of P and 5 mol of Q.
How are excess reactant moles calculated?
Subtract the mass of excess reagent consumed from the total mass of excess reagent provided to determine the amount of excess reactant that is still present.
How many moles of the first reactant, which is 6.75 moles in each balanced equation, react with or produce how many moles of O2?
The answer is 23.6 moles of O2 react with 6.75 moles of C2H6 C 2 H 6 because that is how many moles of O2 we are instructed to find.
How can you locate extra reagent?
The amount of the excess reagent that reacts based on the amount of the limiting reagent is the amount of the reactant that would produce the smallest amount of product; to find the mass of excess reagent, find the amount of the excess reagent that reacts based on that amount; and then deduct that amount from the total amount of excess reagent available.
What exactly is the reactant excess?
Excess reactants, also known as excess reagents, are substances that are not completely consumed or reacted in a chemical reaction. The amount of product formed is independent of the amount of excess reactants.
When 6.42 moles of KClO3 react, how many moles of O2 can be produced?
In order to get moles of KClO3 to cancel out and leave moles of O2 when 6.4 moles of KClO3 break down, you must multiply 6.4 moles of KClO3 by the mole ratio between KClO3 and O2 in the balanced equation.